2sin^2(x)-9cos(y)+3=0

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Solution for 2sin^2(x)-9cos(y)+3=0 equation:


Simplifying
2sin2(x) + -9cos(y) + 3 = 0

Multiply in2s * x
2in2sx + -9cos(y) + 3 = 0

Multiply cos * y
2in2sx + -9cosy + 3 = 0

Reorder the terms:
3 + -9cosy + 2in2sx = 0

Solving
3 + -9cosy + 2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -9cosy + -3 + 2in2sx = 0 + -3

Reorder the terms:
3 + -3 + -9cosy + 2in2sx = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -9cosy + 2in2sx = 0 + -3
-9cosy + 2in2sx = 0 + -3

Combine like terms: 0 + -3 = -3
-9cosy + 2in2sx = -3

Add '-2in2sx' to each side of the equation.
-9cosy + 2in2sx + -2in2sx = -3 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
-9cosy + 0 = -3 + -2in2sx
-9cosy = -3 + -2in2sx

Divide each side by '-9osy'.
c = 0.3333333333o-1s-1y-1 + 0.2222222222in2o-1xy-1

Simplifying
c = 0.3333333333o-1s-1y-1 + 0.2222222222in2o-1xy-1

Reorder the terms:
c = 0.2222222222in2o-1xy-1 + 0.3333333333o-1s-1y-1

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